Question

find sum of all natural numbers less than hundred which are divisible by 6​

Answer 1

Step-by-step explanation:

96 is last term which is less than 100 and divisible by 6

6 is first term

6 is common diffrence

96=a+(n-1)d=tn

96=6+(n-1)6

n=16

S16 = n/2[2a+(n-1)d]=SN

=8[12+90]

=816

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