Find sum of first 12 natural numbers each of which is a multiple of 7
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44
7,14,21,.........upto 12 terms
a=7
d=7
n=12
S12=n/2[2a +(n-1)d]
=12/2[2×7+11×7]
=6[14 + 77]
=6×91
= 546
a=7
d=7
n=12
S12=n/2[2a +(n-1)d]
=12/2[2×7+11×7]
=6[14 + 77]
=6×91
= 546
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