Question

find sum of first 8 multiples of 3

Answer 1

SOLUTION:
The first 8 multiples of 3 are :
 3×1, 3×2 ,3×3, 3×4,.........  3×8
3, 6 ,9, …….., 24
 Here, first term (a) = 3, d= 3, last term (l) = 24, number of terms(n) = 8
 Sum of n terms,Sn = n/2 (a +l)
 Sum of 8 terms , S8 = 8/2(3 + 24)
 S8 = 4 × 27
 S8 = 108
 Hence, the sum of first 8 multiples of 3 is 108.
 HOPE THIS WILL HELP YOU...

Answer 2

Sum refers to the addition operation.

Multiples of a number is the number which is divisible by the number and by 1.

Hence, the first 8 multiples of three would be,

3*1=3

3*2=6

3=3=9

3*4=12

3*5=15

3*6=18

3*7=21

3*8=24

The multiples are 3,6,9,12,15,18,21,24.

Hence their sum,

3+6+9+12+15+18+21+24= 108

The answer is 108.

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