Question

Find sum of zeroes for p(x)=2x^2-x-1​

Answer 1

Step-by-step explanation:

→ P(x) = 2x² - x - 1

→ P(x) = 2x² - 2x + x - 1 = 0

→ P(x) = 2x ( x - 2 ) + 1 ( x - 1 ) = 0

→ P(x) = ( x - 1 ) + ( 2x + 1 ) = 0

• x - 1 = 0
• x = 1

OR

• 2x + 1 = 0
• 2x = -1
• x = $\frac{-1}{2}$

Sum of zeroes = $\frac{-1}{2} {+} {1}$ = $\frac{1}{2}$