Question

Find sum of zeros x^2-3x-1​

Answer 1

Answer:

Given polynomial : p(x) = x² - 3x - 1

On comparing this with ax² + bx + c, we get

• a = 1, b = - 3, c = - 1

Now,

• Sum of zeroes = - b/a

→- (- 3)/1

→ 3/1

→ 3

Hence, the sum of zeroes is 3.

Answer 2

Given :

${x}^{2} - 3x - 1$

To find :

The sum of zeroes of the given polynomial .

Solution :

Compare the given polynomial with the general form of quadratic polynomial ....

$on \: \: comparing \: \: \: \: {x}^{2} - 3x - 1 \: \: \: with \\ a {x}^{2} + bx + c \: \: \: \: \: we \: \: get \: \: \: \\ \\ a = 1 \\ b = - 3 \\ c = - 1 \\ \\ we \: \: know \: \: that \: \: \\ \\ the \: sum \: of \: zeroes \: of \: the \: quadratic \: \\ polynomial \: ( \alpha + \beta ) = \frac{ - b}{a} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{ - 3}{ - 1} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3$

Therefore ,,, the sum of zeroes of x^2 - 3x - 1 is 3 .....

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