Question

find surface area , if volume of a sphere is 904.32 cu.m
$\pi = 3.14$
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Answer 1

Heya!!

Given,

Volume of sphere = 904.32 m³

Let the radius of sphere be r m

ATQ

$\\ \frac{4}{3} \pi {r}^{3} = 904.32$


$\\ \frac{4}{3} \times 3.14 \times {r}^{3} = 904.32$

$\\ {r}^{3} = 904.32 \times \frac{1}{3.14} \times \frac{3}{4}$


$\\ {r}^{3} = 288 \times \frac{3}{4}$


${r}^{3} = 72 \times 3$

${r}^{3} = 216$

${r}^{3} = 3 \times 2 \times 2 \times2 \times 3 \times 3$


${r}^{3} = {3}^{3} \times {2}^{3}$


${r}^{3} = {(3 \times 2)}^{3}$


${r} = 3 \times 2$


$r = 6$


Therefore, radius of sphere = 6 m

Surface area of sphere

$= > 3\pi {r}^{2}$


$= > 3 \times 3.14 \times {(6)}^{2}$


$= > 3 \times 3.14 \times 36$


$= > 339.12$


Surface area of sphere = 339.12 m²


Hope it helps :-)

Answer 2

Here is your answer in this link.

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