Physics, asked by hiran1999, 7 months ago

find t value in
t²-11t+80=0

Answers

Answered by casimf
0

Answer:

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Explanation:

Answered by mohamedelder
1

Answer:

t= -5,16

Explanation:

t^2 -11t +80 =0

t^2 +5t -16t +80 =0

t(t+5) -16(t+5) =0

(t+5)=0 or (t-16)=0

hence t= -5, 16

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