Question

Find ( Take Pi = 3 )
(i) Area of A ?
(ii) Area of B ?
(iii) Total Area of the shape ?

show the workings

Answer 1

Answer:

(1) Area of A = 78.54 m square

(2) Area of B = 60 m square

(3) total area = 108.4 m square

Step-by-step explanation:

( 1 ) radius = diameter /2

= 10/2

= 5 m square

Area of A =

$= \pi {r}^{2}$

$= \frac{22}{7} \times {5}^{2}$

$= \frac{22}{7} \times 25$

$= \frac{550}{7}$

$= 78.54 {m}^{2}$

( 2 ) Area of rectangle

= length × breadth

= 10 × 6

= 60 m square

( 3 ) total area

= 60 + 78.54

= 108.54 metre square

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Answer 2

Solution :

i) Area of A :

• We see the fig. is semi circle

here,

➪ ST = UV = 10m

$\\ \large \sf \leadsto \: radius = \frac{diameter}{2} \\ \\ \large \sf \: r = \frac{10}{2} \\ \\ \large \sf\therefore \: radius = 5m$

Formula :

$\\ \large \sf \mapsto \: \underline{\boxed{ \sf area = \pi {r}^{2} \: }}$

• For semi circle

( half of circle = semi circle)

$\\ \large \rm \implies \: area = \frac{\pi {r}^{2} }{2}$

Given value of pie = 3

Solving :

$\\ \large \sf \implies \:area = \frac{3 \times {5}^{2} }{2} \\ \\ \large \sf \implies \: area = \frac{3 \times {5}^{} \times 5}{2} \\ \\ \large \sf \implies \: area = \: \frac{75 }{2}$

$\large \tt \underline{ \underline{ \star \: \: area = 37.5 {m}^{2} }}$

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ii) Area of B :

• Fig. = rectangle

$\\ \large \sf \leadsto \underline{ \boxed{ \sf \: area = length \times breadth}}$

• Length = 10m

• Breadth = 6m

$\\ \large \rm \implies \: area = 6m \times 10m$

$\large \tt \underline{ \underline{ \star \: \: area = 60{m}^{2} }}$

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iii) area of whole fig.

• Area of whole figure =

$\\ \large \rightarrow \tt \: area \: \: of \: \: (a )+ area \: \: of \: \: (b)$

$\large \implies \sf \: 37.5 {m}^{2} + 60 {m }^{2}$

$\large \tt \underline{ \underline{ \star \: \: area = 97.5{m}^{2} }}$