Question

find tan 2Alpha when sin Alpha=3/5 and Alpha lines in the second quadrant​

Answer 1

Step-by-step explanation:

sinα=3/5 & 90*<α<180*

2sinα

tan2α=__________

1+sin^2α

2(3/5)

=-----------------

1+ (3/5)^2

6/5

=-------------------

1+9/25

6/5

=------------=30/34=15/17

34/25

Answer 2

refer to the attachment