Question

find tan pi/4+A in terms of tan a

Answer 1

Step-by-step explanation:

$\tan( \alpha + \beta ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{1 - \tan( \alpha ) \tan( \beta ) }$

$\tan( \frac{\pi}{4} + a) = \frac{ \tan( \frac{\pi}{4}) + \tan(a) }{1 - \tan( \frac{\pi}{4} ) \tan(a) } = \frac{1 + \tan( a) }{1 - \tan(a) }$

Hope it helps you.