Question

Find tbe distance between two points(6,-7) B(1,5)

Answer 1

Solution :-

According to distance formula we know that, distance between A(a, b) and B(c, d) is equal to :-

• √[(a - c)² + (b - d)²]

comparing given two points coordinates with A(a, b) and B(c, d) we get,

• a = 6
• b = (-7)
• c = 1
• d = 5

then,

→ AB = √[(a - b)² + (c - d)²]

→ AB = √[(6 - 1)² + (-7 - 5)²]

→ AB = √(5² + 12²)

→ AB = √(25 + 144)

→ AB = √(169)

→ AB = 13 units (Ans.)

Hence, tbe distance between two points(6,-7) B(1,5) is 13 units .

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