Find tbe value of k if (1.1) is the solution of the equation 3x-ky=8 .also find the coordinates of another point lying on its graph
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( 1 , 1) is the solution of equation
3x - ky = 8
so, put this equation point (1 , 1)
3 - k = 8
k = 5
so , equation is 3x + 5y = 8
let x = -1 then y = 11/5
x = 0 then y = 8/5
x = 2 then y = 2/5
====================
=======================
so, another points are (-1, 11/5), (0, 8/5) ( 2, 2/5) etc
3x - ky = 8
so, put this equation point (1 , 1)
3 - k = 8
k = 5
so , equation is 3x + 5y = 8
let x = -1 then y = 11/5
x = 0 then y = 8/5
x = 2 then y = 2/5
====================
=======================
so, another points are (-1, 11/5), (0, 8/5) ( 2, 2/5) etc
Answered by
9
if (1,1) is the solution of the given eqn..the it will satisfy eqn..
=) 3x - ky =8. ------------(1)
put x = 1 and y=1 in eqn.. (1) we get..
=) 3-k = 8
=) k = -5 ans...
now the eqn..becomes.
=). 3x + 5y = 8. --------(2)
another point lying on the graph...
put x= 2 in eqn..(2)
=) 3×2 + 5y = 8
=). 6 +5y = 8
=). 5y = 2
=) y = 2/5
so another point lying on the graph is.(2,2/5)
=) 3x - ky =8. ------------(1)
put x = 1 and y=1 in eqn.. (1) we get..
=) 3-k = 8
=) k = -5 ans...
now the eqn..becomes.
=). 3x + 5y = 8. --------(2)
another point lying on the graph...
put x= 2 in eqn..(2)
=) 3×2 + 5y = 8
=). 6 +5y = 8
=). 5y = 2
=) y = 2/5
so another point lying on the graph is.(2,2/5)
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