Question

Find
$find \:6 {x}^{2} - \sqrt{2x } - 2 = 0$
​

Answer 1

Answer:

$6 {x}^{2} - \sqrt{2} x - 2 = 0 \\ 6 {x}^{2} - 3 \sqrt{2} x + 2 \sqrt{2} x - 2 = 0\\ 3x(2x - \sqrt{2} ) + \sqrt{2} (2x - \sqrt{2} ) = 0 \\ (2x - \sqrt{2} )(3x + \sqrt{2} ) = 0 \\ x = \frac{ \sqrt{2} }{2} \: \: \: \: \: \: \: x = \frac{ - \sqrt{2} }{ 3}$

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