Question

find ,

$log( \frac{a + b}{3} ) = \frac{1}{2} log \: ab$

Answer 1

$<h2><font color = red > hey there$



$<font color = black > logarithim$



$log( \frac{a + b}{3} ) = log \sqrt{ab}$



$\frac{a + b}{3} = \sqrt{ab}$



$(a + b) {}^{2} = (3 \sqrt{ab} ) {}^{2}$



$a {}^{2} + b {}^{2} + 2ab = 9ab$



$a {}^{2} + b {}^{2} = 7ab$



$\frac{a {}^{2} + b {}^{2} }{ab} = 7$



$\frac{a}{b} + \frac{b}{a} = 7$



Hope it helps you

Thanks for asking.....



@ Prabhudutt....