Find tge greatest no which divides 626,3127,and 15628 leaving remainders 4,5and6 respectively
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626-4,3127-5,15628-6
=622,3122,15622
622=2x311
3122= 2x7x223
15622=2x7811
therefore hcf=2 hope it helps you!!
=622,3122,15622
622=2x311
3122= 2x7x223
15622=2x7811
therefore hcf=2 hope it helps you!!
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