Question

what effect occurs on the frequency of a pendulum if it is taken from the Earth surface to deep into a mine?

Answer 1

 In deep mine 

g′=g(1−dR)

; i.e., g decreases so according to 

n∝g√,

 frequency also decreases.

Answer 2

Frequency decreases.

Explanation:

The frequency of pendulum depends on length of the pendulum and gravitational acceleration.

$f=\frac{1}{2\pi} \sqrt{\frac{g}{L}}$

With depth, the gravitational acceleration varies as:

$g'=g(1-\frac{d}{R})$

With depth, the gravitational acceleration decreases.

As the frequency of pendulum is proportional to square root of g, so with decrease in g, frequency f would decrease.

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