find tge sum of all natural numbers between 250 and 100 which are divisible by 9
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2802 is the right answer
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Hey,
First no divsible by 9 is =252
a=252
L=99
d=-9
Tn=a+(n-1)d
99=252+(n-1)-9
-261+99=-9n
n=18
Now sm=n/2(a+l)
Sm=9×351
3159 may be your right answer.
First no divsible by 9 is =252
a=252
L=99
d=-9
Tn=a+(n-1)d
99=252+(n-1)-9
-261+99=-9n
n=18
Now sm=n/2(a+l)
Sm=9×351
3159 may be your right answer.
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