Question

Find that mass of Na2CO3 which contains as many Oxygen atoms as present in 3.6 gm C6H12O6


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Answer 1

Answer:3.04 gm of Na2CO3

Explanation:Given mass of C6H12O6 = 3.6gm

Molar mass of C6H12O6 = 180gm

=> For 180gm(1 mole) of C6H12O6 there are 6 moles oxygen atoms

Then for 3.6gm we have

No. of moles of oxygen atoms =

(3.6)(6)/180

= 0.12 moles of oxygen atoms

For 1 mole of Na2CO3 we have 3 moles of oxygen atoms

=> if we want 0.12 moles of oxygen atoms we have to take

(0.12)/3

= 0.04 moles of Na2CO3

Now molar mass of Na2CO3 = 76gm

=> 0.04 moles of Na2CO3 has mass of

= (0.04)(76)

= 3.04 gm

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