Question

Find that value of p for which the quadratic equation

(p + 1)x2

– 6(p + 1)x + 3 (p + 9) = 0, p ≠ -1 had equal roots.​

Answer 1

Step-by-step explanation:

(p+1)×2-6(p+1)x+3(p+9)=0

2p+2-6p-6+3p+27=0

-4p-4+3p+27=0

-p+23=0

-p=-23

p=23(-&- cancelled)