Find the 10" term from end of the AP : 10,7,4,...71
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Answer:
) 1, 4, 7, 10, … ,88. Solution: In order the find the 12th term for the end of an A.P. which has n terms, its done by simply finding the ((n -12) ...
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The sequence given is 10, 7, 4, ....-62.
First we need to find out number of terms in this sequence.
'a' = 10, 'd' = -3, last term = -62
t
n
=a+(n−1)d
⟹−62=10+(n−1)(−3)
⟹−62=13−3n
⟹3n=75orn=25.
The number of terms in the sequence is 25.
The 11th term from the end is same as the 15th term from the first.
So, t
15
=10+(15−1)(−3)
⟹t
15
=10+(14)(−3)
⟹t
15
=−32
.
The 11th term from the end is -32.
hope it helps you ✌️
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