Find the 10th team of arithmetic progression
2.7, 12, using the formule
Answers
Answered by
2
Answer:
10th term is 47
Step-by-step explanation:
a=2
d=7-2=5
n=10
an=a+(n-1)d
=2+(10-1)5
=2+(9)5
=2+45
=47
Answered by
1
Answer:
86.4
Step-by-step explanation:
a=2.7,
d=12-2.7=9.3,
tn=a+(n-1)d
t10=2.7+(10-1)x9.3
=2.7+9x9.3
=2.7+83.7
=86.4
This is how I do
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