Question

The ages of two person are in the ratio 5:7. eighteen years ago their ages were in the ratio 8:13 .find their present age.​

Answer 1

Solution!!

The ratio of ages of two people are given. The ratio of their ages which was eighteen years ago is also given in the question. We have to find their present ages.

Ratio = 5 : 7

Let the ages be 5x and 7x.

18 years ago, the ratio of their ages = 8 : 13

(5x - 18) and (7x - 18)

(5x - 18) ÷ (7x - 18) = 8/13

13(5x - 18) = 8(7x - 18)

65x - 234 = 56x - 144

65x - 56x = 234 - 144

9x = 90

x = 90 ÷ 9

x = 10

5x = 5 × 10 = 50

7x = 7 × 10 = 70

The present ages of two people are 50 years and 70 years, respectively.

Answer 2

Answer:

50,70

Step-by-step explanation:

Their present ages is 50 and 70.

Let Ages of two persons is 5x, 7x

Eighteen years ago their ages were (5x-18), (7x-18) Their ratio is 8:13 so…

(5x-18) / (7x-18) = 8/13

$13(5x-18)=8(7x-18)$

$\: \: \: 65x-234=56x-144 \:$

$\: \: \: 65x-56x=234–144$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 9x=90$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x=10$

Therefore their present ages will be,

5(10), 7(10)

50,70