Question

find the 10th term from end of the AP 8,10,12..........,126.​

Answer 1

Answer 2

Answer:

AP: 8,10,12,...126

a=8,d=2,an=126

Now an=a+(n−1)d

126=8+(n−1)2

⇒118=(n−1)2

⇒59=n−1

⇒n=60

Now 10 th

term from last is (60−10+1) th

term

=51 th

term from beginning

So, a 51

=a+(51−1)d

=8+50×2

=8+100=108

I hope this will help you

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