find the 10th term from the last term of the AP 10,7,4,.............,-62
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Answered by
2
Answer:
The sequence given is 10, 7, 4, ....-62.
First we need to find out number of terms in this sequence.
'a' = 10, 'd' = -3, last term = -62
t
n
=a+(n−1)d
⟹−62=10+(n−1)(−3)
⟹−62=13−3n
⟹3n=75orn=25.
The number of terms in the sequence is 25.
The 11th term from the end is same as the 15th term from the first.
So, t
15
=10+(15−1)(−3)
⟹t
15
=10+(14)(−3)
⟹t
15
=−32
.
The 11th term from the end is -32.
Step-by-step explanation:
#AKsneha
Answered by
0
Answer:
-17
Step-by-step explanation:
a = 10
a+d = 7
using this, d = -3
Now, an = a+(n-1)d
We need n=10
So, a9 = a +9d
= 10 + 9(-3)
=10 + (-27)
= -17
I hope you understood it :)
Thank You!
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