Find the 10th term of an A.p 2,7,12
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nth term of an Ap = a+(n-1)d
a= first term = 2
d = common difference = 5
n= 10
t10 = 2+(10-1)5
= 2+9×5
= 2+45
= 47
So the 10th term of an Ap in the given sequence is 47
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