Question

Find The 10th term of AP 4‚9‚14 .......... 254?

Answer 1

Answer:

Here

a= 4

d= 5

an= 254

so

an= a+(n-1) d

a10= 4+(10-1)5

= 4+45

=50

hence, 10th term is 50

Step-by-step explanation:

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Answer 2

Given: a = 4, d = 5 $\therefore$$(a_2-a_1)$ , an = 254

To find: 10th term

Step-by-step explanation:

According to question

$an=a+(n-1)d$

$254=4+(n-1)5$

$254=4+5n-5$

$254=-1+5n$

$254+1=5n$

$255=5n$

$n=\frac{255}{5}$

$n=51$

10th term is written as

$a+9d$

$4+9\times5$

$4+45$

$=49$

10th term = 49