Question

Find the 10th term of ap from the end . The ap is 5 10 15 ...........485

Answer 1

Answer:

435

Step-by-step explanation:

tn = a+(n-1)d

485 = 5+5n-5

485 = 5n

n = 97

n-10 = 87

t 87 = 5+(86*5)

       =5+430

t 87 = 435

Answer 2

The given AP is 5 10 15 ...........485.

=>First term =5

=>common difference=5

We know that,

$a _{n} = l - (n - 1)d$

$= > a_{10} = 485 - (10 - 1)(5) \\ = > a_{10} = 485 - (9)(5) \\ = > a_{10} =48 5 - 45 \\ = > a_{10} = 440$