Question

Find the 10th term of the A.P., whose first term is 2 and common difference is 5

Answer 1

a₁₀ = a + 9d = 2 + 9(5) = 2+45 = 47

• The 10th(a₁₀) Term is 47 .

Answer 2

Answer:

tn=u+(n-1)*d

2+(10-1)*5

2+9*5

2+45

=47

Step-by-step explanation:

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