Question

find the 10th term of the AP :- 2,7,12,...........
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Answer 1

$\huge\red{\underline{\mathbb{Solution}}}$

a = 2

d = 7-2 = 5

a10 = a +9d

= 2 + 9(5)

= 47

Answer 2

Answer:

a=2

$\small\sf{d=7-2=5}d=7−2=5$

$\small\sf{n=10}n=10$

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$\small\sf{an=a+(n-1)d}an=a+(n−1)d$

$\small\sf{a10=2+(10-1)5}a10=2+(10−1)5$

$\small\sf{2+45}2+452+452+45$

$\small\sf{47}47$

Therefore, the 10th term of the given AP is 47.