Question

Find the 10th term of the gp 5/2 5/4 5/8

Answer 1

Answer:

Step-by-step explanation:

Answer 2

the 10th term of the GP 5/2, 5/4, 5/8, ... is 5/1024.

The given sequence is a geometric progression (GP) with a common ratio of 1/2. To find the 10th term of the GP, we can use the formula:

tn = $ar^{n-1}$

where tn is the nth term of the GP, a is the first term, r is the common ratio, and n is the term number.

In this case, a = 5/2 and r = 1/2, since each term is half the value of the previous term. We want to find the 10th term, so n = 10.

Plugging these values into the formula, we get:

t10 = (5/2)(1/2)^{(10-1)} = (5/2)(1/2)^{9} = (5/2)(1/512) = 5/1024

Therefore, the 10th term of the GP 5/2, 5/4, 5/8, ... is 5/1024.

In summary, we used the formula for the nth term of a GP to find the 10th term of the given sequence with a common ratio of 1/2.
The 10th term is 5/1024, which is the value obtained by multiplying the first term by the common ratio raised to the power of (n-1).

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