Question

Find the 10th term of the sequence 65,56,47,38,…

Answer 1

10th term of an A.P. is -16

Step-by-step explanation:

$a = t_{1} = 65$

$t_{2} = 56$

$t_{3} = 47$

$t_{4} = 38$

$Common \: Difference = t_{2} -t_{1}$

$Common \: Difference =56 - 65$

$Common \: Difference =-9$

We know that,

$a_{n}=a_{1} + (n - 1) \times d$

$a_{10}=65 + (10 - 1) \times ( - d)$

$a_{10}=65 + 9 \times ( - 9)$

$a_{10}=65 + ( - 81)$

$a_{10}= - 16$

10th term of an A.P. is -16