find the 11th term for the last term(towards the first term ) of the AP:10,7,4,.....,-62.
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Answer:
Step-by-step explanation:
Here
a = 10
d = -3
l= -62
Where
l = a+(n-1)d
-62 = 10+(n-1)(-3)
-72 = (n-1)(-3)
n-1 = 24
n = 25
So, there are 25 terms in the given AP.
The 11th term from the last will be the 15th term (it will not be the 14th term )
So,
a15 =10+(15-1)(-3)
= 10-42
= -32
The 11th term from the last is -32
powanna:
Hii, thanks for answering ,but I can't understand after n=25
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