Math, asked by gufarnalam011, 1 year ago

find the 11th term from the end in the ap 56,63,70...., 329.

Answers

Answered by vishalkumarpal

125

a=56
d=a2-a1
d=63-56
d=7
then from last 11th from last then a =329
and d=-7
a11=a+10 d
a11=329-70
a11=259 answer

vishalkumarpal: ya so I slove like this

gufarnalam011: both of u in which class do u read

vishalkumarpal: 10th

001rohit: 10th

gufarnalam011: me 2

gufarnalam011: I want to ask one more question is that. if I will study only ncert then it will be banificial or not.

vishalkumarpal: not because we will study all side book

001rohit: yes

001rohit: rdsharma and evergreen i amsolving

gufarnalam011: I'm rs agarwal nd sample paper of ead together with

Answered by mysticd

Answer:

The 11th term from the end in the ap 56,63,70...., 329 is 259.

Step-by-step explanation:

Given A.P : 56,63,70,...,329

Here,

First term (a) = 56,

common difference (d) = a2-a1

= 63-56

= 7

last term (l) = 329,

where , a+(n-1)d=l

=> 56+(n-1)7=329

Divide each term by 7 , we get

=> 8 + n - 1= 47

=> 7+n = 47

=> n = 47-7

=> n = 40

Now ,

Rearranging the terms from last term to first term, we get

329, 322, ....,70,63,56

Now,

a = 329,

d = 322-329 = -7

n = 11

11th term = a+10d

= 329+10(-7)

= 329-70

= 259

Therefore,

The 11th term from the end in the ap 56,63,70...., 329 is 259.

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