Find the 11th term from the last term (towards the first term) of the AP: 10, 7, 4,.........., -62.?
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Answered by
36
A₁₁=-62+10X3=-62+30=-32
Answered by
64
a = 10 , d = 7 -10 = -3 , l = -62.
no .of terms = l = a + ( n-1 ) d.
-62 = 10 +(n-1)(-3)
-72=(n-1)(-3)
n-1 =24
n= 25.
so, there are 25 terms...in the given AP.
n- p+1
=> 25-11+1 =15.
so..the last term from the last Will be15th term series.
so, a15 = 10+(15-1)(-3)=10-42.
=> -32.
so, the last term from the end is -32.
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