Question

find the 127th term of an A.P...108,100,92,84.​

Answer 1

$\huge\tt\colorbox{orange}{Answer}$

$a1 = 108 \\ d = a2 - a1 \\ d = 100 - 108 \\ d = - 8$

$a127 = a + 126d \\ = 108 + 126( - 8) \\ = 108 - 1008 \\ = - 900$

$127th \: \: term \: is \: - 900$

Answer 2

$\large\bf{\underline\green{☕︎Good \: Morning☕︎}}$

a = 108

d = -8

n = 127

an = a + (n-1)d

= 108 + (127-1)-8

= 108 + (126)(-8)

= 108 - 1008

= 900

Therefore, 900 is the 127th term of the given AP.