find the 12th term from the end of the following AP first 3,5,7,9, .....201
Answers
Answered by
3
Step-by-step explanation:
first term a=3
common diff.(d)=2
a12=a+11d
=3+11.2
=25
Answered by
0
Answer:
179
Step-by-step explanation:
3, 5, 7, 9 ....... 201
1st method
to find the term from last we write the series in reverse
201, 199, 197..........3
a = 201 d = -2
an = a + (n-1)d
a12 = 201 + (12-1)-2
= 201 + (11×-2)
= 201 - 22
= 179
179 is the 12th term from end.
2nd method
find total number of term where last term is 201
an = a + (n-1)×d
201 = 3 + (n-1)×2
201 - 3 = (n-1)×2
198 = (n-1)×2
n - 1 = 198/2
n - 1 = 99
n = 99 + 1 = 100
there are 100 terms in total
12 term from last Will be the 89th term from first
a89 = 3 + (89-1) × 2
= 3 + 88(2)
= 3 + 176
= 179
hope you get your answer
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