Math, asked by sanjeevanisahay29030, 1 year ago

find the 12th term of a GP whose 8th term is 192 and the common ratio is 12

Answers

Answered by Anonymous
5

Answer:

If a₁ is the first term,  is the nth term and r is the common ratio of the given G.P. series then

=a₁rⁿ⁻¹

a₈=a₁×(2)⁸⁻¹=192

or, a₁×2⁷=192

or, a₁=192/2⁷

or, a₁=2⁶×3/2⁷

or, a₁=3/2

∴, a₁₂=a₁r¹²⁻¹

=3/2×(2)¹¹

=3×(2)¹⁰

=3×1024

=3072



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