Question

Find the 12th term of A.P root 2,3 root 3, 5 root 2 .....?

Answer 1

$a12 = a + 11d \\ ap.. \sqrt{2} \: \sqrt[3]{3} \: \sqrt[5]{2} \\ d = a2 - a1 \\ d = \sqrt[3]{3} - \sqrt{2} = 3.781 \\ a12 = \sqrt{2} + 11(3.781) \\ a12 = 43 \\ \\ mark \: me \: as \: brainliest$