Find the 12th term of AP.√2, 3√2,5√2......
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a12= A1+11d
a12= ✓2+11(2✓2)
a12=✓2+22✓2
a12=23✓2
a12= ✓2+11(2✓2)
a12=✓2+22✓2
a12=23✓2
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