Question

Find the 12th term of the arithmetic sequence whose common difference is d=9 and whose first term is av1=1.

Answer 1

Correct Question :

Find the 12th term of the arithmetic sequence whose common difference is d=9 and whose first term is a= 1

Solution :

We have :

First term ,a=1

Common difference,d = 9

We know:

The gernal term of an Ap

$\tt\:a_{n}=a+(n-1)d$

We have to find 12th term of AP

$\sf\:a_{12}=a+(12-1)d$

$\sf=a+11d$

$\sf=1+11\times9$

$\sf=1+99$

$\sf=100$

Therefore,

The 12th term of Arithmetic progression is 100 .

$\rule{200}2$

More About Arithmetic Progression:

Sum of n terms of an AP given by :

$\sf \: S_{n} = \dfrac{1}{2}(2a+ (n - 1)d)$

Answer 2

Answer:

Refer to the attachment..........