Find the joint equation of lines passing through (3,2) and parallel to the lines x=2 and y=3.
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Given : lines passing through (3,2) and parallel to the lines x=2 and y=3.
To find : joint equation of lines
Solution:
Line parallel to x = 2
x = c₁
Line parallel to y = 3
y = c₂
Line passes through ( 3 , 2)
=> x = 3 => x - 3 = 0
y = 2 => y - 2 = 0
joint equation of lines x = 3 & y = 2
is (x - 3)(y - 2) = 0
=> xy - 2x - 3y + 6 = 0
xy - 2x - 3y + 6 = 0 is the joint equation of lines passing through (3,2) and parallel to the lines x=2 and y=3.
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