Question

find the 14th term from the end of G.P 3,6,12....3072​

Answer 1

The nth term of a GP series is Tn = ar^n-1

where.

a = first term and

r = common ratio = (Tn/Tn-1)

so, 14th term will

t14 = 3× 2^(14-1)

= 3 × 2^13

= 24576