Find the 15th term of an A.P where the 3rd term is 8 and the common difference is 1 /3.
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Answered by
0
Answer:
12
Step-by-step explanation:
common difference (d) = 1/3
3rd term = 8
a + 2d = 8
a + (2 × 1/3) = 8
a + 2/3 = 8
a = 8-2/3 = 22/3
a = 22/3
a15 ( 15th term) = a + (15 -1 ) d
15th term = 22/3 + 14/3
15th term = 36/3 = 12
15th term = 12
Answered by
0
Step-by-step explanation:
given t3=8 and d =1/3
so first we find the value of a by using third term value.
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