Question

Find the 15th term of an arithmatic progression whose first term is 2 and the common difference is 3

Answer 1

i hope this will help

Answer 2

$\huge \bold{ANSWER}$

An arthimetic progression is a sequmience of numbers in which each term can be obtained by adding a certain quantity to its proceeding term.

◼Difference between two consecutive terms is called common difference d.

Given,

First term (a) = 2

Common difference (d) =3

To find 15th term use formula,

$t_n = a + (n-1) \times d$

$t_{15} = 2 + (15-1) \times 3$

$t_{15} = 2 + 14 \times 3$

$t_{15} = 2 + 42$

$t_{15} = 44$