Question

Find the terms of an arithmatic progression with the first term 2 and last term being 62 given that common difference is 2

Answer 1

30 terms will be there

Answer 2

a=2
d=2
an=62
n=(an-a/d)+1
(62-2/2)+1
(60/2)+1
30+1
31
Therefore number of terms =31
OR
an=a+(n-1)d
62=2+(n-1)2
62=2+2n-2. {by expanding bracket}
62=2n
n=62/2
n=31