Question

Find the 15th term of AP with second term 11 and common difference 9

Answer 1

Heya Kiddo !!

==> Let a be the first term and d be the common difference

Given : a2 = 11 and common difference d = 9

==> a2 = a + d

by substituting the value of d and a2 in above equation we have,

11 = a + 9

==> a = 11 - 9

==> a = 2

Now,

15th term is given by

a15 = a + 14d

on substituting both a and d in above equation we get,

==> a15 = 2 + 14 X 9

==> 2 + 126

==> a15 = 128

Hope it helps you ❤❤❤

Answer 2

Consider a 11 as the first term of ap
therefore a=11
d=9
a15=a+14d
a15=11+14×9
a15=24×9
a15=216
Therefore a15=216