Question

Find the 16th term of an A.P.

9, 12, 15, 18……​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$a = 9$

$d = 12 - 9 = 3$

$tn = a + (n - 1)d$

$t16 = 9 + (16 - 1)3$

$= 9 + 15 \times 3$

$= 9 + 45 = 54$

$t16 = 54$

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