Math, asked by studygirl1808, 16 days ago

Find the 16y² + x². if 4y + x = 7 and xy = 3.​

Answers

Answered by Raeeba
0

Answer:

-47

Step-by-step explanation:

16y^2 + x^2 = (4y+x)^2 - 16×2xy

Replacing 4y+x with 7,

16y^2 + x^2 = (7)^2 -32xy

16y^2 + x^2 = 49 -32 xy

Now, replacing xy with 3,

16y^2 + x^2 = 49-32×3

16y^2 + x^2= -47

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Answered by ritajha991
0

16y² + x²

( 4y2) + (x) 2

(4y+x) (4y+x)

7*7

49 Ans

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