find the zeros of the polynomial √5x^2-7x-6√5 and verify he relation between coefficient of the polynomial
Answers
Step-by-step explanation:
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Given : √5x²-7x-6√5
To Find : zeros of the polynomial
verify the relation between coefficient of the polynomial
Solution:
√5x²-7x- 6√5
= √5x²-10x + 3x - 6√5
= √5x(x - 2√5) + 3(x - 2√5)
= (√5x + 3)(x - 2√5)
To find Zeroes equate each factor with 0
=> √5x + 3 = 0 => x = - 3/ √5
x - 2√5 = 0 => x = 2√5
Zeroes are - 3/ √5 , 2√5
Sum of Zeroes = (-3/√5 + 2√5) = 7/√5
Product of Zeroes = (- 3/ √5) ( 2√5) = - 6
ax² + bx + c
Sum of zeroes =- b/a = - (-7)/ √5 = 7/√5
product of zeroes = c/a = -6√5 / √5 = - 6
Verified
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