find the 17th term and r^th term of the series 12,9,3.....
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3
Answer:
-36
Step-by-step explanation:
a=12
d=9-12=-3
n= 17
17th term = a+ (n-1)d
=12 + (17-1)-3
=12 +(16×(-3))
=12 - 48
=-36
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